Laurenso


\usepackage{amsmath}
\usepackage{tikz}

\newcommand*\circled[1]{\tikz[baseline=(char.base)]{%
\node[shape=circle, draw, minimum size=1.5em, inner sep=0pt , thick] (char) {#1};}}
\renewcommand\choicelabel{\circled{\Alph{choice}}}
\renewcommand{\questionshook}{%
\settowidth{\leftmargin}{0pt}}
\renewcommand{\choiceshook}{\settowidth{\leftmargin}{\circled{W}.\hskip\labelsep\hskip 0em}}
\newcommand{\correctchoicelabel}{\fbox{\thechoice}}
\CorrectChoiceEmphasis{\renewcommand{\choicelabel}{\correctchoicelabel}}
\usepackage[left=1.7cm,right=1.7cm,top=1.5cm,bottom=2cm]{geometry}

\begin{document}
\section{Questions}
\begin{questions}
\question What is 2+2?

\begin{oneparchoices} %<<<<<<<<<<< with  blank line before
\choice $x^2 + y^2 = 8$
\choice $\dfrac{x^2 - x + m}{x+ 5}$
\choice 3
\CorrectChoice 4
\end{oneparchoices}

\question What is 2+2?
\begin{oneparchoices}

\choice 1
\CorrectChoice 4
\choice 2
\choice 3
\end{oneparchoices}

\question What is the result of $y = x^3 - 3x^2 + 7x - 1$?

\begin{oneparchoices}
\choice $y' = 3x^2 - 6x + \dfrac{5}{x} - \sin x + \cos x$
\choice $y' = 3x^2 - 6x + \dfrac{5}{x} - \sin x + \cos x$
\CorrectChoice $y' = 3x^2 - 6x + 7$
\choice 4
\end{oneparchoices}

\question What is the result of $1+1$?

\begin{oneparchoices}
\choice 1
\CorrectChoice 2
\choice 3
\choice 4
\end{oneparchoices}

\end{questions}

\subsection{Keys}
\centering
\printkeytable
\end{document}


![image.png](/image?hash=873f0cb4ed9a995423b8ac73d8e6ae1ff50b9588c07427f6cc17bb1a1da3c1fb)

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