\documentclass[12pt,a4paper]{article}\usepackage{tabularray}\usepackage{fouriernc}\usepackage{mathtools}\UseTblrLibrary{amsmath, booktabs,
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\usepackage{enumitem}\usepackage{ninecolors}\usepackage{amssymb}\usepackage{siunitx}\sisetup{output-decimal-marker={,}}\usepackage[paperwidth=19cm, paperheight=26.5cm,
hmargin=1.7cm,
vmargin={1.8cm,1.7cm}]{geometry}\newcounter{mycnta}\newcommand{\mycnta}{\stepcounter{mycnta}\arabic{mycnta}}\begin{document} \begin{longtblr}[ caption={The function $y = \dfrac{(x-a)(x-b)}{(x-c)(x-d)}$ }]{ colspec = {cllcc}, cells={mode=dmath}, row{1}={mode=text}, }
Order & Function $y = f(x)$ & $y'= f'(x)$ & Point $A$ & Point $B$\\ \hline
\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\ \mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\ \mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\ \mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\ \mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\ \mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\\mycnta &y=\dfrac{(x+15) (x+50)}{(x+5) (x+10)} & y'=-\dfrac{50 \left(x^2+28 x+160\right)}{(x+5)^2 (x+10)^2} & (-20,-1) & (-8,-49) \\ \end{longtblr}
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