How to draw a part of a cylinder and a plane? - TeX

marmot replying to Anonymous 1123

I think so, yes.

Anonymous 1123

@marmot, re: [your answer](#a1894), Is it the same [here](https://tex.stackexchange.com/questions/595476/draw-a-wedge-with-circular-base-in-tikz)?

Anonymous 1123 replying to marmot

Thanks. Too nice.

marmot replying to Anonymous 1123

A simple version could be  
```  
\documentclass[tikz,border=3mm]{standalone}
\usetikzlibrary{calc,3dtools}% https://github.com/marmotghost/tikz-3dtools
\begin{document}
\begin{tikzpicture}[line cap=round,line join=round,
	3d/install view={phi=0,theta=70},
	declare function={R=3;H=4;h=2.5;},
	same bounding box=A]
 \fill[blue] (-R,0,0) arc[start angle=180,end angle=360,radius=R]
  -- (R,0,h) arc[start angle=360,end angle=180,radius=R] -- cycle;
 \fill[blue!50] (0,0,h) circle[radius=R];
 \pic{3d/frustum={r=R,R=R,h=H}};
\end{tikzpicture}
\end{document}
```

Anonymous 1123 replying to marmot

 Can `3dtools` reduce [this answer](https://tex.stackexchange.com/questions/462774/drawing-a-tank-with-water-in-it)?

marmot replying to Anonymous 1123

Yes, IMHO this is much better than guessing hard-coded coordinates and hoping that they are an orthonormal projection or using external tools to get those coordinates.

Anonymous 1123 replying to marmot

I use this code to answer [this question](https://tex.stackexchange.com/questions/593285/change-direction-of-axis-tikzpicture)

Anonymous 1123 replying to marmot

Yes. Thanks.

marmot replying to Anonymous 1123

In this case I think the above code is simpler. You can probably (I did not test)  use  
```  
\tikzset{3d/define orthonormal dreibein={A={(0,0,0)},B={(1,0,0)},C={(0,1,0)}}}
```   
but IMHO it is less direct. It only makes sense if the directions are not along the usual unit vectors and/or are not normalized.

Anonymous 1123 replying to marmot

How can I use this syntax   
```  
\tikzset{3d/define orthonormal dreibein}
	\begin{scope}[x={(ex)},y={(ey)}]  
```  
in your code?

Anonymous 1123 replying to marmot

Thanks. I understand your code.

marmot replying to Anonymous 1123

Sure.

Anonymous 1123 replying to marmot

Thanks. Can I copy this code to answer?

marmot replying to Anonymous 1123

I think the OP may want something like   
```  
\documentclass[tikz,border=3mm]{standalone}
\usetikzlibrary{calc,3dtools}% https://github.com/marmotghost/tikz-3dtools
\begin{document}
\foreach \Angle in {5,15,...,355}
{
\begin{tikzpicture}[line cap=round,line join=round,
	c/.style={circle,fill,inner sep=1pt}, 
	3d/install view={phi=\Angle,theta=70},same bounding box=A]
   \path (1,0,0) coordinate (ez) (0,1,0) coordinate (ex)
	(0,0,1) coordinate (ey);
   \begin{scope}[x={(ex)},y={(ey)},z={(ez)}] 
	  \draw[-stealth] (0,0,0) -- (5,0,0) node[pos=1.05]{$x$};
	  \draw[-stealth] (0,0,0) -- (0,5,0) node[pos=1.05]{$y$};
	  \draw[-stealth] (0,0,0) -- (0,0,5) node[pos=1.05]{$z$};
      \path
         (0,0,0) coordinate (O)
        (4,0,0) coordinate (B)
        (4,2,0) coordinate (A)
        (0,2,0) coordinate (D)
        (0,0,4) coordinate (O')
        (4,0,4) coordinate (B')
        (4,2,4) coordinate (A')
        (0,2,4) coordinate (P)
        (2,1,2) coordinate (T);   
	  \tikzset{3d/polyhedron/.cd,O={(T)},fore/.append style={fill=none},
            back/.append style={3d/hidden},
            draw face with corners={{(O)},{(B)},{(A)},{(D)}},
            draw face with corners={{(A)},{(B)},{(B')},{(A')}},
            draw face with corners={{(O)},{(D)},{(P)}},draw face with corners={{(O)},{(O')},{(P)}},
            draw face with corners={{(A')},{(B')},{(O')},{(P)}},
            draw face with corners={{(A)},{(D)},{(P)}},
            draw face with corners={{(A)},{(A')},{(P)}},
            draw face with corners={{(O)},{(B)},{(B')},{(O')}}}
      \path foreach \p/\g in {A/-90,O/-90,P/90}{(\p)node[c]{}+(\g:2.5mm) node{$\p$}}; 
      \draw[3d/hidden]  (O) -- (A) ;
  \end{scope}
\end{tikzpicture}}
\end{document}    
```  
![ani.gif](/image?hash=f8ec42269f9f97ed9e0db0a9eed78bd85c4df12b2f114e81a2dfaaf926b733aa)

Anonymous 1123 replying to marmot

Thanks.

marmot replying to Anonymous 1123

I am sorry, I cannot follow. Please try to be as precise as possible.

Anonymous 1123 replying to marmot

But I can not do like OP'request. Please see OP'comment.

Anonymous 1123 replying to marmot

First is incorrect. Now corrected.  I diveded two ractangles into two triangles. For example: `,
				draw face with corners={{(A)},{(D)},{(P)}},
				draw face with corners={{(A)},{(A')},{(P)}},`

marmot replying to Anonymous 1123

I did not see any incorrect lines. Please tell me which lines you think are incorrect.

Anonymous 1123 replying to marmot

Some dashed line incorrect. I repair  
```  
\documentclass[tikz,border=3mm]{standalone}
\usetikzlibrary{calc,3dtools}% https://github.com/marmotghost/tikz-3dtools
\begin{document}
\foreach \Angle in {5,15,...,355}
{
	\begin{tikzpicture}[line cap=round,line join=round,c/.style={circle,fill,inner sep=1pt}, 3d/install view={phi=\Angle,psi=0,theta=70},same bounding box=A]
			\path
			 (0,0,0) coordinate (O)
			(4,0,0) coordinate (B)
			(4,2,0) coordinate (A)
			(0,2,0) coordinate (D)
			(0,0,4) coordinate (O')
			(4,0,4) coordinate (B')
			(4,2,4) coordinate (A')
			(0,2,4) coordinate (P)
			(2,1,2) coordinate (T)
			;	\tikzset{3d/polyhedron/.cd,O={(T)},fore/.append style={fill=none},
				back/.append style={3d/hidden},
				draw face with corners={{(O)},{(B)},{(A)},{(D)}},
				draw face with corners={{(A)},{(B)},{(B')},{(A')}},
				draw face with corners={{(O)},{(D)},{(P)}},draw face with corners={{(O)},{(O')},{(P)}},
				draw face with corners={{(A')},{(B')},{(O')},{(P)}},
				draw face with corners={{(A)},{(D)},{(P)}},
				draw face with corners={{(A)},{(A')},{(P)}},
				draw face with corners={{(O)},{(B)},{(B')},{(O')}}}
\path foreach \p/\g in {A/-90,O/-90,P/90}{(\p)node[c]{}+(\g:2.5mm) node{$\p$}}; 
\draw[3d/hidden]  (O) -- (A) ;
\end{tikzpicture}}
\end{document}  
```

marmot replying to Anonymous 1123

You have to run the code twice that the bounding box is correct.  
![ani.gif](/image?hash=d270d7308efbabae8a0ca7e429327e254250e00be2680e3f4be4de4388462ba4)

Anonymous 1123 replying to marmot

It seems not nice  
![cube.gif](/image?hash=3700601ab8bfd762354ba6d2c3aef4b056428feaa0e9edfaa1bf2f5d20c18d7b)

Anonymous 1123 replying to marmot

I am trying to answer [this question]( https://tex.stackexchange.com/questions/593344/how-to-rotate-a-3d-axis-some-options-of-the-axis-doesnt-work/593428#593428)  
My code  
```    
\documentclass[tikz,border=3mm]{standalone}
\usetikzlibrary{calc,3dtools}% https://github.com/marmotghost/tikz-3dtools
\begin{document}
\foreach \Angle in {5,15,...,355}
{
	\begin{tikzpicture}[line cap=round,line join=round,c/.style={circle,fill,inner sep=1pt}, 3d/install view={phi=\Angle,psi=0,theta=70},same bounding box=A]
			\path
			 (0,0,0) coordinate (O)
			(4,0,0) coordinate (B)
			(4,2,0) coordinate (A)
			(0,2,0) coordinate (D)
			(0,0,4) coordinate (O')
			(4,0,4) coordinate (B')
			(4,2,4) coordinate (A')
			(0,2,4) coordinate (P)
			(2,1,2) coordinate (T)
			;	\tikzset{3d/polyhedron/.cd,O={(T)},fore/.append style={fill=none},
				back/.append style={3d/hidden},
				draw face with corners={{(O)},{(B)},{(A)},{(D)}},
				draw face with corners={{(A)},{(B)},{(B')},{(A')}},
				draw face with corners={{(O)},{(D)},{(P)},{(O')}},
				draw face with corners={{(A')},{(B')},{(O')},{(P)}},
				draw face with corners={{(A)},{(D)},{(P)},{(A')}},
				draw face with corners={{(O)},{(B)},{(B')},{(O')}}}

\path foreach \p/\g in {A/-90,O/-90,P/90}{(\p)node[c]{}+(\g:2.5mm) node{$\p$}}; 
\draw[3d/hidden]  (O) -- (A) -- (P) -- cycle
;
\end{tikzpicture}}
\end{document}  

```

Anonymous 1123 replying to marmot

Yes. Thanks.

marmot replying to Anonymous 1123

```  
\documentclass[tikz,border=3mm]{standalone}
\usetikzlibrary{calc,3dtools}% https://github.com/marmotghost/tikz-3dtools
\begin{document}
\begin{tikzpicture}[3d/install view={phi=0,theta=70},scale=1,line cap=butt,line join=round,c/.style={circle,fill,inner sep=1pt},
	declare function={r=3;h=3;myr=3;}] 
	\path 
	(0,0,0) coordinate (O)
	(0,0,h) coordinate (O');
	\draw[3d/visible,fill=gray!50,even odd rule] (O') circle[radius=myr] 
	(O') circle[radius=myr/2];
	\draw[3d/visible,left color=gray,right color=gray,middle color=gray!50]
	 (O') circle[radius=myr/2];
	\draw[3d/visible,left color=gray!50,right color=gray!50,middle color=gray!20] 
	 (-myr,0) arc[start angle=-180,end angle=0,radius=myr]
	 -- (myr,0|-O') arc[start angle=0,end angle=-180,radius=myr]
	 -- cycle;
\end{tikzpicture}
\end{document}    
```  
![Screen Shot 2021-04-17 at 9.09.25 AM.png](/image?hash=6100d968ab25f4d1da898df20d16afc5969c38a726b884bed985c3dab1f3f525)

Anonymous 1123 replying to marmot

Can it be like this?  ![ScreenHunter 96.png](/image?hash=1cfdda4b3c68567aef00529820a60f1d4a2c5bbfba533bf6d4f420b34b506bc5)

marmot replying to Anonymous 1123

Or this?  
```  
\documentclass[tikz,border=3mm]{standalone}
\usetikzlibrary{calc,3dtools}% https://github.com/marmotghost/tikz-3dtools
\begin{document}
\begin{tikzpicture}[3d/install view={phi=0,theta=70},scale=1,line cap=butt,line join=round,c/.style={circle,fill,inner sep=1pt},
	declare function={r=3;h=3;myr=3;}] 
	\path 
	(0,0,0) coordinate (O)
	(0,0,h) coordinate (O');
	\draw[3d/visible,fill=gray!50,even odd rule] (O') circle[radius=myr] 
	(O') circle[radius=myr/2];
	\draw[3d/visible,left color=gray,right color=gray,middle color=gray!50]
	 (O') circle[radius=myr/2];
	\draw[3d/visible,left color=gray!50,right color=gray!50,middle color=gray!20] 
	 (-myr,0) arc[start angle=-180,end angle=0,radius=myr]
	 -- (myr,0|-O') arc[start angle=0,end angle=-180,radius=myr]
	 -- cycle;
\end{tikzpicture}
\end{document}    
```  
![Screen Shot 2021-04-17 at 9.07.59 AM.png](/image?hash=0200fa218842a22349c3e00492999043b7e442d6d8fc44cbd87d54054804eeda)

marmot replying to Anonymous 1123

I do not understand your question. The *question* seems to be pretty clear. The answer is is a bit voluminous, but it also distinguishes some cases.

marmot replying to Anonymous 1123

Like this?  
```  
\documentclass[tikz,border=3mm]{standalone}
\usetikzlibrary{calc,3dtools}% https://github.com/marmotghost/tikz-3dtools
\begin{document}
\begin{tikzpicture}[3d/install view={phi=0,theta=70},scale=1,line cap=butt,line join=round,c/.style={circle,fill,inner sep=1pt},
	declare function={r=3;h=3;myr=3;}] 
	\path 
	(0,0,0) coordinate (O)
	(0,0,h) coordinate (O');
	\draw[3d/visible,fill=gray!50,even odd rule] (O') circle[radius=myr] 
	(O') circle[radius=myr/2];

	\draw[3d/visible] (-myr,0) arc[start angle=-180,end angle=0,radius=myr]
	([xshift=-myr*1cm]O) -- ([xshift=-myr*1cm]O')
	([xshift=myr*1cm]O) -- ([xshift=myr*1cm]O');
\end{tikzpicture}
\end{document}    
```

Anonymous 1123

@marmot, re: [your answer](#a1894), How can fill cylinder [like this](https://tex.stackexchange.com/questions/508480/how-can-fill-between-two-cylinders-to-create-holes-in-cylinders) (not contain dashlines).  
My code  
```  
\documentclass[tikz,border=3mm]{standalone}
\usetikzlibrary{calc,3dtools}% https://github.com/marmotghost/tikz-3dtools
\begin{document}
\begin{tikzpicture}[3d/install view={phi=0,theta=70},scale=1,line cap=butt,line join=round,c/.style={circle,fill,inner sep=1pt},
	declare function={r=3;h=3;myr=3;}] 
	\path 
	(0,0,0) coordinate (O)
	(0,0,h) coordinate (O');
	\draw[3d/visible,] (O') circle[radius=myr] 
	(O') circle[radius=myr/2]
	([xshift=-myr*1cm]O) -- ([xshift=-myr*1cm]O')
	([xshift=myr*1cm]O) -- ([xshift=myr*1cm]O')
	(-myr,0) arc[start angle=-180,end angle=0,radius=myr]
	;
	
	%\path foreach \p/\g in {O'/90,O/-90}{(\p)node[c]{}+(\g:2.5mm) node{$\p$}};
	%\draw[3d/hidden] (O) -- (O');
\end{tikzpicture}
\end{document}    
```
```

Anonymous 1123

@marmot, re: [your answer](#a1894), Can you rewrite the answer of [this question](https://tex.stackexchange.com/questions/432511/fill-cylinder-in-latex)? It is difficult for me to understand.

1 Answer