Replacing last match of substring - *nix

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Top Answer

Jack Douglas

Inspired by [this answer on unix.se](https://unix.stackexchange.com/a/426833), you can sandwich the replacement text between the leading and trailing parts:

::: tio S0oszvj/v7ikyDYxKdnRydnQyBjCUFDgSk3OyFdQUqkGyqoCBbVqKyqrwDxlZS0gv1bp/38A
§§§ bash bash
str=abcABC123abcABC  
echo "${str%abc*}xyz${str##*abc}"
§§§
``` none
abcABC123xyzABC
```
:::

comments

transcript

prabhjot drake

Jack Douglas

but   basically you need this:
~~~  
` bash  
echo "Wat it do"

Jack Douglas replying to prabhjot drake

have a look at the post Peter linked to at the top of this thread

prabhjot drake replying to PeterVandivier

How TIO works?

prabhjot drake

```:  bash
echo "Wat it do"
```

prabhjot drake replying to PeterVandivier

Thanks to you and @JackDouglas for puting your time and effort in Q.

prabhjot drake replying to Jack Douglas

Thanks for answer.

Jack Douglas

::: tio S0oszvj/v7ikyDYxKdnRydnQyBjCUFDgSk3OyFdQUqkGyqoCBbVqKyqrwDxlZS0gv1bp/38A
§§§ bash bash
str=abcABC123abcABC  
echo "${str%abc*}xyz${str##*abc}"
§§§
``` none
abcABC123xyzABC
```
:::

PeterVandivier

::: tio S0oszvj/v7ikyDYxKdnRydnQyBjCUFDgSk3OyFdQqQZK6gPF9Csqq2pRReHC//8DAA
§§§ bash bash
str=abcABC123abcABC  
echo ${str/abc/xyz}  
echo ${str//abc/xyz}
§§§
``` none
xyzABC123abcABC
xyzABC123xyzABC
```
:::

prabhjot drake

 Btw abc=Uninitialized

prabhjot drake

`echo ${abc/b/x}` gives nothing. `echo foo' gives foo.

prabhjot drake

I want `abcABC123xyzABC`. This is all I want.

prabhjot drake

Output: xyzABC123xyzABC

prabhjot drake

`$ echo ${str//abc/xyz}`

prabhjot drake

Output: xyzABC123abcABC

prabhjot drake

`$ echo ${str/abc/xyz}`

prabhjot drake

`str=abcABC123abcABC`

PeterVandivier

@@@ question 997

PeterVandivier

can you provide a tio example of what you see? syntax is   
  
```  
` bash  
echo foo  
echo ${abc/b/x}
```

PeterVandivier

::: tio S0oszvj/PzU5I18hLT@fC8xQqU5MStZP0q@o/f8fAA
§§§ bash bash
echo foo
echo ${abc/b/x}
§§§
``` none
foo

```
:::

1 Answer