prabhjot drake
I'm using a variable that contains multi-line string. When I write
```bash
echo -n "This is a two
line string."
```
`echo -n` does not suppress newline. So far as I know `-n` ( or `\c` on some systems) suppresses newlines. What I'm missing?
PS: OS: Linux Mint
Bash version
`GNU bash, version 4.4.20(1)-release (i686-pc-linux-gnu)`
Top Answer
PeterVandivier
As noted in the [`echo` man page](https://linux.die.net/man/1/echo), `-n` suppresses only the final trailing newline
> -n
>
> do not output the trailing newline
If you you want to remove the newline character from the body of a block of text, [`tr`](https://linux.die.net/man/1/tr) is the function for you. In the following example the `-d` flag indicates we should delete all instances of the selected character `\n` which is interpreted as "newline". Note the `-n` flag on `echo` is optional in this usage.
```bash
echo -n "This is a two
line string." | tr -d '\n'
```
[tio](https://tio.run/##S0oszvj/PzU5I19BN09BKSQjs1gBiBIVSsrzubhyMvNSFYpLijLz0vWUFGoUSooUdFMU1GPy1P//BwA)
