Jonathan Mee
I know that a const char* is a pointer to a constant character, and that a const char[] is an array of constant characters.

That said what should make me prefer declaring as one type over the other? Are there any good heuristics for directing that decision?
Jonathan Mee
The simple answer is that when declaring a variable you should prefer a const char[].

---

To understand this let's take 2 character strings: const char* ptr = "lorem" and const char arr[] = "ipsum" And lets pass them into this function:

template <typename T>
void Output(const void* pv, const char pc[], T ppc) {
std::cout << "Value: " << pv << " String: " << pc << " Address: " << ppc << std::endl;
}

Output(ptr, ptr, &ptr) will output something like:

> Value: 00E33130 String: lorem   Address: 00FBF8D8

While Output(arr, arr, &arr) will output something like:

> Value: 00FBF8DC   String: ipsum   Address: 00FBF8DC

The notable difference here is that ptr requires the allocation of another address. There are 3 extra expenses to this.

1. The 1^st^ is the obvious memory cost of a pointer, which one would expect that to be as simple as 8-bytes on a 64-bit architecture, [but because of relocations that can skyrocket to 32-bytes of memory](https://glandium.org/blog/?p=2361)
1. [The 2^nd^ is the hidden cost of indirection, and potential cache misses](https://eklitzke.org/declaring-c-string-constants-the-right-way)
1. The final expense is in the requirement of separately finding the end of the string pointed to by ptr, whereas arr can use the [Range Access Functions](https://en.cppreference.com/w/cpp/iterator#Range_access)

If we were to change ptr to a _constant_ pointer (const char* const ptr) the result would be the compiler optimizing away **1**, however both **2** and **3** would persist _and_ ptr could not be used in functions taking a const char*. Ultimately, when declaring variables const char[] is the clear choice over both const char* and const char* const.

Enter question or answer id or url (and optionally further answer ids/urls from the same question) from

Separate each id/url with a space. No need to list your own answers; they will be imported automatically.