I want use method of base class when my derived class has method with the same name but with different arguments. 

If I just try to call base method I've got a compile time error:

> *.cpp: In function 'int main()':  
> *.cpp:25:11: error: no matching function for call to 'Derived::foo()'  
>     p1.foo();  
>            ^  
> *.cpp:13:7: note: candidate: 'void Derived::foo(int)'  
>   void foo(int c)  
>        ^~~  
> *.cpp:13:7: note:   candidate expects 1 argument, 0 provided  
> Compilation failed.

Here is code:

    #include <iostream>

    struct Base
    {
	    void foo()
	    {
		    std::cout<<"Base foo\n";
	    }
    };
    
    struct Derived : public Base
    {
	    void foo(int c)
	    {
		    (void)c;
		    std::cout<<"Derived foo";
	    }
    };
    
    int main()
    {
       Derived p1;
       p1.foo();
    }

So how to access the base method if derived method is hiding the base one?